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Question

The oxidation state of iodine in $${ H }_{ 4 }I{ O }_{ 6 }^{ \ominus  }$$ is :


A
+7
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B
1
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C
+5
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D
+1
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Solution

The correct option is A $$+7$$
Let $$x$$ be the oxidation state of $$I$$ in $$H_4IO_6^\ominus $$.
Since, the overall charge on the complex is $$-1$$, the sum of oxidation states of all elements in it should be equal to $$-1$$.
Therefore,
$$+4+x + 6(-2) = -1$$
or, $$x = +7$$
Hence, the oxidation state of $$I$$ is $$+7$$.

Chemistry

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