Question

The oxidation state of nitrogen in $N_{3}H$ is

• A. $+\frac{1}{3}$
• B. $+3$
• C. $-1$
• D. $-\frac{1}{3}$

Answer 1

The correct option is D $-\frac{1}{3}$

In hydrazoic acid $\left(N_{3}H\right),$ nitrogen shows $-\frac{1}{3}$ oxidation state.

$\stackrel{\ast }{N_3}H$

Let, $x$ be the oxidation state of nitrogen.

Now,

$3x+1=0;\Rightarrow x=-\frac{1}{3}$