Question

The oxidation state of P in $H_{3}P{O}_4$ is :

• A. + 3
• B. + 5
• C. + 7
• D. None of these

Answer 1

The correct option is B + 5

We know that oxidation state of $O=-2,H=+1$

Now, let's assume oxidation state of $P=x$

So, $x+4\times (-2)+3\times (+1)=0$

$\Rightarrow x-8+3=0$

$\Rightarrow x=+5$

Hence the oxidation state of P in $H_{3}P{O}_4$ is $+5$.

Therefore option $\left(B\right)$ is correct.