The P-V diagram of a system undergoing thermodynamic transformation is shown in figure. The work done on the system in going from A→B→C is 50 J and 20 calheat is given to the system. The change in internal energy between A and C is
A
34 J
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B
70 J
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C
84 J
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D
134 J
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Solution
The correct option is D134 J Heat given ΔQ=20cal=20×4.2=84J. Work done ΔW=−50J[As process is anticlockwise] By first law of thermodynamics ⇒ΔU=ΔQ−ΔW=84−(−50)=134J