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Question

The P-V diagram of a system undergoing thermodynamic transformation is shown in figure. The work done on the system in going from ABC is 50 J and 20 calheat is given to the system. The change in internal energy between A and C is

A
34 J
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B
70 J
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C
84 J
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D
134 J
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Solution

The correct option is D 134 J
Heat given ΔQ=20 cal=20×4.2=84J.
Work done ΔW=50J [As process is anticlockwise]
By first law of thermodynamics ΔU=ΔQΔW=84(50)=134J

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