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Question

The pair of boiling point and compound are given as,
$$C_6 H_6,$$      $$CH_3OH$$     $$C_6H_5NO_2$$     $$C_6H_5NH_2$$
 $$80^oC$$          $$65^oC$$          $$212^oC$$               $$184^oC$$    
    (I)              (II)            (III)                  (IV)
Which will show lowest vapour pressure at room temperature?


A
C6H6
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B
CH3OH
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C
C6H5NO2
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D
C6H5NH2
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Solution

The correct option is C $$C_6H_5NO_2$$
As the boiling point is inversely proportional to vapour pressure hence, nitrobenzene having bp $$212^oC$$ will show the lowest vapour pressure at room temperature. 

This is because low vapour pressure makes the substance more non-volatile and thus increase its boiling point.

Option C is correct.

Chemistry

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