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Preparations and Uses of Caustic Soda

The pair of c...

Question

The pair of compounds which cannot exist together in solution is:

A

N a H C O_{3}

and

N a O H

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B

N a_{2} C O_{3}

and

N a H C O_{3}

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C

N a_{2} C O_{3}

and

N a O H

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D

N a H C O_{3}

and

N a C l

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Solution

The correct option is A $N a H C O_{3}$ and $N a O H$
The pair of compounds which cannot exist together in solution is $N a H C O_{3}$ and $N a O H$ .

$N a H C O_{3}$ and $N a O H$ cannot coexist in solution because $N a H C O_{3}$ is an acid salt. It reacts with the base $N a O H$ as follows:

$N a H C O_{3} + N a O H ⟶ N a_{2} C O_{3} + H_{2} O$

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Similar questions

Q. A sample contains a mixture of

N a H C O_{3}

N a_{2} C O_{3}

H C l

15.0

g of the sample yielding

11.0

N a C l

. What percent of the sample is

N a_{2} C O_{3}

?
Reactions are:

N a_{2} C O_{3} + 2 H C l \to 2 N a C l + C O_{2} + H_{2} O

N a H C O_{3} + H C l \to N a C l + C O_{2} + H_{2} O

Molecular weight of

N a C l

N a H C O_{3}

N a_{2} C O_{3}

58.5

84

106

g/mol respectively.

Q. A mixture of

N a H C O_{3}

N a_{2} C O_{3}

weighed .0235 g. The dissolved mixture was reacted with excess of

8 a (O H)_{2}

2.1028 g B a C O_{3}

, by the following reactions:

N a_{2} C O_{3} + B a (O H)_{2} \to B a C O_{3} + 2 N a O H

N a H C O_{3} + B a (O H)_{2} \to B a C O_{3} + N a O H + H_{2} O

What was the percentage of

N a H C O_{3}

in the original mixture ?

Q. The valency factor of

N a_{2} C O_{3}

in the given reaction is

N a_{2} C O_{3} B a s e + H C l A c i d \to N a H C O_{3} + N a C l

Q. A 2 g sample containing

N a_{2} C O_{3}

N a H C O_{3}

loses 0.62 g when heated to

300^{o} C,

the temperature at which

N a H C O_{3}

N a_{2} C O_{3}, C O_{2}

H_{2} O .

What is the percentage of

N a_{2} C O_{3}

in the given mixture.

0.6234

g sample that might contain

N a O H, N a_{2} C O_{3}, N a H C O_{3}

or a mixture of

N a O H + N a_{2} C O_{3}

N a_{2} C O_{3} + N a H C O_{3}

is titrated with

0.1062 M H C l

by two-indicator method. It is found that

40.38

mL of the acid is required to reach the phenolphthalein end-point. Methyl orange is then added to the solution and the titration continued using an additional

12.83

mL of the acid. Thus, the sample contained :

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