The pair of linear equations 3x+5y=3,6x+ky=8 do not have any solution if
A
k=5
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B
k=10
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C
k≠10
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D
k≠5
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Solution
The correct option is Ck=10 The equation are 3x+5y−3=0 ....(1) 6x+ky−8=0 .....(2) Here, a1=3,b1=5,c1=−3 and a2=6,b2=k,c2=−8 The given system has no solution if a1a2=b1b2≠c1c2 ⇒36=5k≠−3−8 ⇒3k=30⇒k=10