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Question

The pairs of linear equations whose solution is  x = 2, y = –3 are


  1. x + y = –1 ; 2x – 3y = –5

  2. 2x + 5y = –11 ; 4x + 10y = –22

  3. 2x – y = 1 ; 3x + 2y = 0

  4. x – 4y –14 = 0 ; 5x – y – 13 = 0


Solution

The correct options are
A

x + y = –1 ; 2x – 3y = –5


D

x – 4y –14 = 0 ; 5x – y – 13 = 0



x + y = –1  x = -1 - y......(i)

2x + 3y = –5........(ii)

Substituting (i) in (ii) we get 

2 (-1 - y) + 3y = -5      y = -3

From (i)    

x = -1- (-3) 

   = 2
(alternate method)

x - 4y = 14.....(i)

5x - y = 13.....(ii)

Substitute x = 2, y = –3 in the two given equations and check if it satisfies,

In (i) :  2 - 4(-3) = 14  (satisfies)

In (ii) : 5 (2) - (-3) = 13 (satisfies)

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