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Ostwald Dilution Law

The percentag...

Question

The percentage of pyridine $(C_{5} H_{5} N)$ that forms pyridinum ion $(C_{5} H_{5} N^{+} H)$ in a $0.10 M$ aqueous pyridine solution $(G i v e n - K_{b}, f o r C_{5} H_{5} N = 1.7 \times 10^{- 9})$ is?

0.0060 %

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0.013 %

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0.77 %

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1.6 %

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Solution

The correct option is B $0.013 %$

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