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Question

The perimeter of a rectangle is $$40\ cm$$. The length of rectangle is more than double its breadth by $$2\ cm$$. Find the length and breadth of rectangle .


Solution

Perimeter of rectangle $$= 40$$ cm (given)

condition :- length = $$2\times $$ breadth $$+2$$
$$\Rightarrow l=2b+2$$

perimeter $$p = 2(l+b) = 40$$
$$\Rightarrow 2(2b+2+b)=40$$
$$\Rightarrow 2(3b+2)=40$$
$$\Rightarrow 6b=40-4=36$$
$$\therefore b=6 cm$$

$$l=2\times 6+2 = 12+2= 14 cm$$

$$\therefore $$ length $$= 14$$ cm, breadth $$= 6$$ cm

Mathematics

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