Question

# The perimeter of a rectangle is $$40\ cm$$. The length of rectangle is more than double its breadth by $$2\ cm$$. Find the length and breadth of rectangle .

Solution

## Perimeter of rectangle $$= 40$$ cm (given)condition :- length = $$2\times$$ breadth $$+2$$$$\Rightarrow l=2b+2$$perimeter $$p = 2(l+b) = 40$$$$\Rightarrow 2(2b+2+b)=40$$$$\Rightarrow 2(3b+2)=40$$$$\Rightarrow 6b=40-4=36$$$$\therefore b=6 cm$$$$l=2\times 6+2 = 12+2= 14 cm$$$$\therefore$$ length $$= 14$$ cm, breadth $$= 6$$ cmMathematics

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