The perimeter of an isosceles triangle is $50 c m$ . If one of the two equal sides is $18 c m$ , find the third side.

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Solution

Let, the triangle be $△ A B C$
Given, $A B = C A = 18 c m$
Perimeter of the $△ A B C = 50 c m$
$\Rightarrow A B + B C + C A = 50 c m$
$\Rightarrow 18 c m + B C + 18 c m = 50 c m$
$\Rightarrow B C = 50 c m - 36 c m = 14 c m$

Hence, Third side $B C = 14 c m$ .

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