Question

The perimeter of an isosceles triangle is $$50\ cm$$. If one of the two equal sides is $$18\ cm$$, find the third side.

Solution

Let, the triangle be $$\triangle ABC$$Given, $$AB = CA = 18\ cm$$Perimeter of the $$\triangle ABC = 50\ cm$$$$\Rightarrow AB + BC + CA = 50\ cm$$$$\Rightarrow 18\ cm + BC + 18\ cm = 50\ cm$$$$\Rightarrow BC = 50\ cm - 36\ cm = 14\ cm$$Hence, Third side $$BC = 14\ cm$$.Mathematics

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