The perimeter of floor of a rectangular hall is $250 m$ . If its height is $6 m$ , find the cost of painting its four walls at the rate of Rs. $20$ per meter square.

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Solution

Given, height of rectangular hall $= 6 m$
Perimeter of floor of rectangular hall $= 250 m$
We know that Perimeter of rectangle $= 2 (l + b) = 250$
Area of four walls $= 2 (l + b) h$ , Where $2 (l + b) = 250$
Thus, Area of four wall $= 250 \times 6 = 1500 m^{2}$
Therefore, Cost of painting four walls $=$ rate $\times$ area
$= R s . 20 \times 1500$
$= R s . 30, 000$

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The perimeter of floor of a rectangular hall is 250 m. If its height is 6 m, find the cost of painting its four walls at the rate of Rs. 20 per meter square.

Given, height of rectangular hall =6 mPerimeter of floor of rectangular hall =250 mWe know that Perimeter of rectangle=2(l+b)=250Area of four walls =2(l+b)h , Where 2(l+b)=250Thus, Area of four wall=250×6=1500 m2 Therefore, Cost of painting four walls =rate × area =Rs. 20×1500=Rs. 30,000

The perimeter of floor of a rectangular hall is $250 m$ . If its height is $6 m$ , find the cost of painting its four walls at the rate of Rs. $20$ per meter square.