The perimeter of the figure ABCDEFGHIJ is

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Solution

Perimeter = Sum of all sides
So, AJ + JI + IH + HG + GF + FE + ED + CD + BC + AB
= (AJ + IH + GF + BC) + 3 + 5 + 2 + 20 + 4 + 6
= DE + 40 $[∵ A J + I H + G F + B C = D E]$
= 20 + 40 = 60 cm

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The perimeter of the figure ABCDEFGHIJ is

Perimeter = Sum of all sides So, AJ + JI + IH + HG + GF + FE + ED + CD + BC + AB = (AJ + IH + GF + BC) + 3 + 5 + 2 + 20 + 4 + 6 = DE + 40 [∵AJ+IH+GF+BC=DE] = 20 + 40 = 60 cm

Perimeter = Sum of all sides
So, AJ + JI + IH + HG + GF + FE + ED + CD + BC + AB
= (AJ + IH + GF + BC) + 3 + 5 + 2 + 20 + 4 + 6
= DE + 40 $[∵ A J + I H + G F + B C = D E]$
= 20 + 40 = 60 cm