Given, Perimeter of one square = 40 m
Suppose the length of square = a1
So, 4a1= 40 m Side (a1) = 40 ÷ 4 = 10 m
Area of a square = a1×a1=10×10=100m2
Perimeter of second square = 96 m
Suppose the length of square = a2
So, 4a2 = 96 m Side (a2) = 96 × 4 = 24 m
Area of a square = a2×a2=24×24=576m2
As we know, perimeter of another square is equal in area to the sum of the first two square.
So, area of another square = 100 + 576 = 676 m
Area of a square = a3×a3
676 = (a3)2ora3=26
Thus, perimeter = 4a3=4×26=104m