The period of oscillation of a simple pendulum is T=2π√Lg. Measure of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. The accuracy in the determination of g?
The correct option is (A) 2.7%
Step 1, Given data
Time period T=2π√Lg
L = 20 cm
Step 2, Finding the accuracy
We know,
Time period is
T=2π√Lg
Squaring on both sides and rearranging,
g=4π2LT2