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Question

The period of simple pendulum is measured as $$T$$ in a stationary lift. If the lift moves upward with an acceleration of  $$5\ g$$, the period will be


A
The same
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B
Increased by 3/5
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C
Decreased by 2/3 times
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D
None of the above
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Solution

The correct option is D None of the above
$$T=2\pi\sqrt{\dfrac{l}{g}}\\T\propto \sqrt{\dfrac{1}{g}}$$
$$\dfrac {T'}{T}=\sqrt {\dfrac {g}{g+a}}=\sqrt {\dfrac {g}{g+5g}}=\sqrt {\dfrac {1}{6}}$$

$$\Rightarrow T' =\dfrac {T}{\sqrt 6}$$

Physics

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