Question

The period of small oscillations of a pendulum, that is bob suspended by a thread L = 20 cm in length, if it is located in a liquid whose density is 3 times less than that of bob is 5+x10 second (approximately). Find the value of x. ___

Solution

geff=Weight−UpthrustMass =vρg−vρ3gvρ=23g T=2π√Lgeff=2π√3L2g=2π√3×0.22×9.8 or T≃1.1s=5+610s ⇒x=6

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