Question

# The periodic of oscillation of a simple pendulum of constant length at earth surface is $$T$$. Its period inside a mine is

A
Greater than T
B
Less than T
C
Equal to T
D
Cannot be compared

Solution

## The correct option is A Greater than $$T$$Inside the mine $$g$$ decreasehence form $$T=2\pi \sqrt {\dfrac lg}: T$$ increasePhysics

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