CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The periodic time of a body executing simple harmonic motion is $$3$$ sec. After much interval form time $$t=0$$, its displacement will be half of its amplitude. 


A
18sec
loader
B
16sec
loader
C
14sec
loader
D
13sec
loader

Solution

The correct option is C $$\dfrac 14 sec$$
Given that, time period $$T= 3seconds$$.
The equation for SHM is given by, 
$$y=Asin \omega t$$ and $$\omega = 2\pi f=\frac{2\pi}{T}$$
Let after time $$t=t$$, the displacement is half its amplitude, 
$$\Rightarrow \frac{A}{2}=Asin(\frac{2\pi}{3}t)$$
$$\Rightarrow sin(\frac{\pi}{6})= sin(\frac{2\pi t}{3})$$
$$\Rightarrow \frac{\pi}{6}=\frac{2\pi t}{3}$$
or, $$t=\frac{1}{4} sec $$ is our required answer.

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image