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Question

The perpendicular bisector of the line segment joining P(1,4)andQ(K,3) has y-intercept -4 Then a possible value of K is

A
-4
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B
1
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C
2
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D
-2
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Solution

The correct option is C -4
Slope of PQ=34k1=1k1=11k

Slope of perpendicular bisector of PQ=11k =k1

(1+k2,72)(k1)

y72=(k1)(x1+k2)

2y72=(k1)(2x1k2)

(2yk)=(k1)(2x1k)

(2y7)=2xkkk22x+1+k

2x(1k)+2y+k28=0

For y-intercept x=0,

2y+k28=0

2y=8k2

y=4k22

Given y-intercept=4

4k22=4

k22=8

k2=16

k=±4

1204586_1244816_ans_627cdb9f301246e6a3b9f68492ee3f65.JPG

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