Question

# The $$pH$$ of $$0.1$$M aqueous solutions of $$NaCl$$, $$CH_3COONa$$ and $$NH_4Cl$$ will follow the order:

A
NaCl<CH3COONa<NH4Cl
B
NH4Cl<NaCl<CH3COONa
C
NH4Cl<CH3COONa<NaCl
D
NaCl<NH4Cl<CH3COONa

Solution

## The correct option is C $$NH_4Cl < NaCl < CH_3COONa$$The order of pH is $$\displaystyle NH_4Cl \text {( less than 7)} < NaCl (7) < CH_3COONa \text {( more than 7)}$$Hence, the option (B) is correct answer.$$\displaystyle NH_4Cl$$ is a salt of weak base and strong acid. Its solution is acidic.$$\displaystyle CH_3COONa$$  is a salt of weak acid and strong base. Its solution is basic.$$\displaystyle NaCl$$  is a salt of strong base and strong acid. Its solution is neutral.Chemistry

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