The $p H$ of $10^{- 5} M$ aqueous solution of $N a O H$ is:

5

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7

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9

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11

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Solution

The correct option is C $9$
$N a O H = N a^{+} + O H^{-}$

$[O H^{-}] = 10^{- 5} M; [H^{+}] [O H^{-}] = 10^{- 14}$

$[H^{+}] = \frac{10^{- 14}}{10^{- 5}}; [H^{+}] = 10^{- 9} M; p H = 9$

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