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Question

The pH of the solution 5 mL of M5HCl+10mL of M10NaOH is:

A
5
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B
3
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C
7
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D
8
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Solution

The correct option is C 7
Find milliequivalents of HCl and NaOH and then find which is in excess to know pH of resulting solution.
Given, vol. of HCl=5 ml, molarity = M/5
Vol. of NaOH=10 mL, molarity = M/10
Milliequivalents of HCl =5×15=1
Milliequivalents of NaOH =10×110=1
HCl+NaOHNaCl+H2O
Milliequivalents of HCl= Milliequivalent of NaOH
Solution is neutral and pH=7

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