Question

# The pH  of the solution obtained by mixing equal volumes of solution of $$pH=5$$ and $$pH=3$$ of the same electrolyte is:

A
3.3
B
4.0
C
4.5
D
2.0

Solution

## The correct option is A $$3.3$$Sample-1:$$pH=5$$$$pH=-log[H^+]=5$$$$\Rightarrow [{ H }^{ + }]=10^ {-5}M = (M_1)$$$$V_1=V_0$$Sample2:$$pH=3$$$$pH=-log[H^+]=3$$$$\Rightarrow [{ H }^{ + }]=10^ {-3}M = (M_2)$$$$V_2=V_0$$The concentration of the mixture of two solutions will be $$MV=M_1V_1+M_2V_2$$$$M(V_0+V_0)=(10^{-5})V_0+(10^{-3})V_0$$$$\Rightarrow M=\cfrac {10^{-5}+10^{-3}}{2}=0.000505$$$$pH=-log[H^+]=-log(0.000505)=-(-3.29)=3.3$$Chemistry

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