The photoelectric work function for a metal surface is 3.84×10−19J. If the light of wavelength 5000˚A is incident on the surface of the metal, will there be photoelectric emission?
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Solution
Given that ;
Work function (ϕ)=3.84×10−19J
wavelength of incident light =λ=5000˚A
λ=5000˚A=5000×10−10m=5×10−7m
The Energy of the incident radiation is
E=hcλ
⇒6.62×10−34×3×1085×10−7
E=3.972×10−19J
∴E>ϕ
As E is greater than ϕ. So, photoelectric emmission will occur.