Question

# The photoelectric work function for a metal surface is $$3.84 \times 10^{-19} J$$. If the light of wavelength $$5000 \mathring{A}$$ is incident on the surface of the metal, will there be photoelectric emission?

Solution

## Given that ;Work function $$(\phi) = 3.84 \times 10^{-19} J$$wavelength of incident light $$= \lambda = 5000 \mathring{A}$$$$\lambda = 5000 \mathring{A} = 5000 \times 10^{-10} m = 5 \times 10^{-7} m$$The Energy of the incident radiation is $$E = \dfrac{hc}{\lambda}$$$$\Rightarrow \dfrac{6.62 \times 10^{-34} \times 3 \times 10^8}{5 \times 10^{-7}}$$$$E = 3.972 \times 10^{-19}J$$$$\therefore E > \phi$$As E is greater than $$\phi$$. So, photoelectric emmission will occur.PhysicsNCERTStandard XII

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