The picnic spot is 55 km away. The first stop is taken at 22 km from the school. percentage of the distance is remaining to reach the destination.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 60
Distance of the picnic spot from the school = 55 km.
Distance travelled before taking first stop = 22 km.
Remaining distance = 55 - 22 = 33 km
Therefore, percentage of distance remaining is:
$\frac{33}{55} \times 100 = 60 %$ .

Suggest Corrections

Similar questions

A picnic spot is 55 km away from the school. The first stop between the school and the spot is taken at 22 km from the school. What percentage of the distance is remaining to reach the destination?

The picnic spot is 55 km away from a school. The first stop is taken at 22 km from the school. What percentage of the distance is remaining to reach the destination?

Q. A picnic spot is 55 km away from a school. The first stop is taken at 22 km from the school. What percentage of the distance is remaining to reach the destination?

A picnic spot is $55$ km away from a school. The first stop is taken at $22$ km from the school. What percentage of the distance is remaining to reach the destination?

Q. A picnic spot is 55 yards away from a school. The school bus stops at 22 yards away from the school. What percentage of distance remains to reach the picnic spot?

Join BYJU'S Learning Program

The picnic spot is 55 km away. The first stop is taken at 22 km from the school. percentage of the distance is remaining to reach the destination.

The correct option is A 60Distance of the picnic spot from the school = 55 km. Distance travelled before taking first stop = 22 km. Remaining distance = 55 - 22 = 33 km Therefore, percentage of distance remaining is: 3355×100=60%.

The correct option is A 60
Distance of the picnic spot from the school = 55 km.
Distance travelled before taking first stop = 22 km.
Remaining distance = 55 - 22 = 33 km
Therefore, percentage of distance remaining is:
$\frac{33}{55} \times 100 = 60 %$ .