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Question

The pKa of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA  in which 50% of the acid is ionized is:
  1. 4.5
  2. 2.5
  3. 9.5
  4. 7


Solution

The correct option is C 9.5
For buffer solution 
pH=pKa+log[Salt][Acid]
pH=4.5+log[Salt][Acid]
The reaction is  HA (acid)A (salt)+H+ .
As the acid is 50% ionized, then same  amount of salt is formed.
Therefore, [Salt] = [Acid]
pH=4.5pH+pOH=14pOH=144.5=9.5

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