Question

The plastic modulus of a section is $4.8\times {10}^{-4}{m}^3$. If the plastic moment capacity of the section is 120 kN-m, then the yield stress of the material is ______MPa.

Answer 1

$M_p=Z_p.{\sigma }_y$

$\Rightarrow 120\times {10}^6=4.8\times {10}^{-4}\times {10}^9\times {\sigma }_y$

$\Rightarrow {\sigma }_y=\frac{120\times {10}^6}{4.8\times {10}^{-4}\times {10}^9}=250MPa$