Question

The plate resistance of a triode valve is $3\times {10}^3\Omega$ and its mutual conductance is $1.5\times {10}^{-3}$ A/V. The amplification factor of the triode is?

• A. $5\times {10}^{-5}$
• B. $4.5$
• C. $0.45$
• D. $2\times {10}^6$

Answer 1

Answer: (B)

$4.5$

Amplitude factor is given by :

$AF=R\times C$

where $R$ is plate resistance of a triode valve and

$C$ is mutual conductance.

$R=3\times {10}^3\Omega$

$C=1.5\times {10}^{-3}A/V$

$AF=3\times {10}^3\times 1.5\times {10}^{-3}=4.5$

Option B is correct.