The point (b,3) lie on the graph of the linear equation 2x-3y+11=0 find b.

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Solution

Since the point (b,3) lies on the graph of 2x-3y+11 the point satisfy the linear equation 2x-3y+11=0.
i.e, 2b-33+11=0
2b-9+11=0
2b=-2
b=-1
.

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