Question

# The points $$(3,3) (h,0)$$ and $$(0,k)$$ are collinear, if $$\dfrac{1}{h}+\dfrac{1}{k}$$ is equal to

A
12
B
13
C
1
D
2

Solution

## The correct option is B $$\dfrac{1}{3}$$A line is passing through $$(3,3),(h,0),(0,k)$$ due to they are collinear. Its $$x$$-intercept is $$h$$ and $$y$$-intercept is $$k$$.Line intercept form is $$\dfrac{x}{h}+\dfrac{y}{k}=1$$Line pass through $$(3,3)\Rightarrow \dfrac{3}{h}+\dfrac{3}{k}=1$$$$\Rightarrow \dfrac{1}{h}+\dfrac{1}{k}=\dfrac{1}{3}$$So, answer is option B.Mathematics

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