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Question

The points $$(3,3) (h,0)$$ and $$(0,k)$$ are collinear, if $$\dfrac{1}{h}+\dfrac{1}{k}$$ is equal to


A
12
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B
13
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C
1
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D
2
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Solution

The correct option is B $$\dfrac{1}{3}$$
A line is passing through $$(3,3),(h,0),(0,k)$$ due to they are collinear. 
Its $$x$$-intercept is $$h$$ and $$y$$-intercept is $$k$$.
Line intercept form is $$\dfrac{x}{h}+\dfrac{y}{k}=1$$
Line pass through $$(3,3)\Rightarrow  \dfrac{3}{h}+\dfrac{3}{k}=1$$
$$\Rightarrow  \dfrac{1}{h}+\dfrac{1}{k}=\dfrac{1}{3}$$
So, answer is option B.

Mathematics

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