The points A(0, 6), B(-5, 3) and C(3, 1) are the vertices of a triangle which is
Right-angled isosceles
AB2=(52+32)=34,BC2={(−8)2+22}=68,AC2=(−3)2+(5)2=34
∴ AB=AC.
Hence, ΔABC is isosceles.
and AB2 + AC2 = 34 + 34
= 68
=BC2
∴ It is a right angle triangle also.
Hence, ΔABC is right-angled isosceles triangle.