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Question

The points A(-4, 0), B(4, 0) and C(0, 3) are the vertices of a triangle, which is

(a) isosceles (b) equilateral (c) scalene (d) right angled

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Solution


Let A(-4,0), B(4,0) and C(0,3) are the given vertices.
Now, distance between A(-4,0) and B(4,0),
AB=(4(4))2+(00)2
=(4+4)2=64=8
Distance between B(4,0) and C(0,3),
BC=(04)2+(30)2=(16+9)=25=5
Distance between A(-4,0) and C(0,3)
AC=([0(4)]2+(30)2)=(16+9)=25=5
BC=AC
Hence, ΔABC is an isosceles triangle because an isosceles triangle has two sides equal.


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