The Poisson’s ratio of the material is 0.5. If a force is applied to a wire of this material, there is a decrease in the cross sectional area by 4%. The percentage increase in its length is
Given Poisson's ration= 0.5
It shows that the density of material is constant
Therefore the change in volume of the wire is zero
Thus
V=A×l = constant
log V=log A+log |
therefore △ VV=0=△ AA+△ ll
△ ll=−△ AA
or % increase in length=△ ll×100
=-(-4)
=4%