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Question

The position of an object by ¯r=(9t^i+4t3^j)m. Find its velocity at time t = 1 s.

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Solution

We know that velocity at any instant is nothing but time derivative of position at that instant. So v=dr/dt=(9^i+12t2^j)m/s
So put t=1s we get v=(9^i+12^j)m/s

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