The position of the particle is given by $x = 2 t^{2} + 6 t + 2$ in $m$ . The instantaneous speed of the particle at $6 sec$ is

20 m/s

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30 m/s

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24 m/s

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36 m/s

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Solution

The correct option is B $30 m/s$
As we know that the instantaneous speed of the particle is given by
$\frac{d x}{d t} = \frac{d (2 t^{2} + 6 t + 2)}{d t}$
$\Rightarrow v = 4 t + 6$
So, $v |_{@ t=6 sec} = 4 \times 6 + 6 = 30 m/s$

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