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Question

The position vector of a particle is r=(a cos ωt)^i+(a sin ωt)^j. The velocity of the particle is


  1. Parallel to the position vector

  2. Perpendicular to the position vector

  3. Directed towards the origin

  4. Directed away from the origin


Solution

The correct option is B

Perpendicular to the position vector


r=(a cos ωt)^i+(a sin ωt)^j
v=drdt=aω sin ωt^i+aω cos ωt^j
As r.v=0 therefore velocity of the particle is perpendicular to the position vector.

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