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Question

The positive value of K for which the equation x2 + kx + 64 = 0 has equal roots is :


A

16

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B

-16

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C

8

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D

-8

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Solution

The correct option is

A

16



x2 + kx + 64 = 0
Here a = 1, b = k and c = 64
To have equal roots
b2 – 4ac = 0
Therefore, (k)2 – 4 (1) 64 = 0
k2 – 256 = 0
k2 = 256
k = 16
k = 16 is the positive value of k.


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