The potential difference $V_{B} - V_{A}$ is

- 100 [2 + \sqrt{3}] V

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100 [2 + \sqrt{3}] V

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100 [2 - \sqrt{3}] V

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- 100 [2 - \sqrt{3}] V

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Solution

The correct option is A $- 100 [2 + \sqrt{3}] V$
$d_{1} = A O c o s 30^{0} = 2 \sqrt{3} / 2 = \sqrt{3} m$
$d_{2} = B o s i n 30^{0} = 4 \times \frac{1}{2} = 2 m$
$V_{A} - V_{0} = E d_{1} = 100 \sqrt{3} V$
$\Rightarrow V_{0} - V_{A} = - 100 \sqrt{3} V$
$V_{A} - V_{B} = E (d_{1} + d_{2}) = 100 (\sqrt{3} + 2) V$
$\Rightarrow V_{B} - V_{A} = - 100 (\sqrt{3} + 2) V$

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