The potential energy at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively:

$90^{\circ}$ and $180^{\circ}$

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$0^{\circ}$ and $90^{\circ}$

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$90^{\circ}$ and $0^{\circ}$

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$0^{\circ}$ and $180^{\circ}$

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Solution

The correct option is D
$0^{\circ}$ and $180^{\circ}$

$V = \frac{K P c o s θ}{r^{2}} V \propto c o s θ V_{m a x} a t θ = 0^{\circ} V_{m i n} a t θ = 180^{\circ}$

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The potential energy at a point due to an electric dipole will be maximum and minimum when the angles between the axis of the dipole and the line joining the point to the dipole are respectively:

The correct option is D 0∘ and 180∘ V=KPcosθr2V∝cosθVmax atθ=0∘Vmin atθ=180∘

The correct option is D
$0^{\circ}$ and $180^{\circ}$

$V = \frac{K P c o s θ}{r^{2}} V \propto c o s θ V_{m a x} a t θ = 0^{\circ} V_{m i n} a t θ = 180^{\circ}$