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Question

The potential energy of a certain particle is given by U=12(x2y2). The force on it is:

A
x^i+y^j
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B
x^i+z^k
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C
x^iy^j
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D
x^iy^j
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Solution

The correct option is A x^i+y^j
Fx=Ux=x(x2y22)=x
Fy=Uy=y(x2y22)=y
F=x^i+y^j

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