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Question
The potential energy of a particle is determined by the expression U=α(x2+y2), where α is a positive constant. The particle begins to move from a point with the coordinates (3, 3) (m), only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the
coordinates (1, 1) (m) is
The potential energy of a particle is determined by the expression U=α(x2+y2), where α is a positive constant. The particle begins to move from a point with the coordinates (3, 3) (m), only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the
coordinates (1, 1) (m) is
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Solution
The correct option is C 16α
As the particle moves only under the action of conservative force so its mechanical energy must be conserved. So dT + dU = 0 (T stands for kinetic energy )
or, ΔT=−ΔU=Ui−Uf
=α(32+32)−α(12+12)
=18α−2α=16α.
As the particle moves only under the action of conservative force so its mechanical energy must be conserved. So dT + dU = 0 (T stands for kinetic energy )
or, ΔT=−ΔU=Ui−Uf
=α(32+32)−α(12+12)
=18α−2α=16α.
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