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Question

The potential energy of a particle of mass m is given by,

U(x)={E0;0x10;x>1

λ1 and λ2 are the de-Broglie wavelengths of the particle, when 0x1 and x>1 respectively. If the total energy of particle is 2E0, then ratio λ1λ2 will be

A
2
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B
1
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C
2
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D
12
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Solution

The correct option is C 2
Given, Total Energy=2E0

For, (0x1) P.E=E0

K.E=2E0E0=E0

λ1=h2mE0

For, (x>1) P.E=0

K.E=2E0

λ2=h4mE0

λ1λ2=2

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.

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