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Misconceptions about PE

The potential...

Question

The potential energy of spring is given by $U = \frac{1}{2} k x^{2}$ , where x is extension spring. Find the force associated with this potential energy in y direction.

Z e r o

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k x

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- k x

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\frac{k x}{2}

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Solution

The correct option is A $Z e r o$
$F_{x} = \frac{- \partial u}{\partial x}$

$= - k x$

$F_{y} = 0$

$F_{z} = 0$

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