Question

# The precipitate of $$Ca{ F }_{ 2 }\left( { K }_{ sp }=1.7\times { 10 }^{ -10 } \right)$$ is obtained when equal volumes of which of the following are mixed?

A
104 M Ca2++104 M F
B
102 M Ca2++103 M F
C
105 M Ca2++103 M F
D
103 M Ca2++105 M F

Solution

## The correct option is C $${ 10 }^{ -2 }\ M\ { Ca }^{ 2+ }+{ 10 }^{ -3 }\ M\ { F }^{ - }$$The ionic product $$\displaystyle IP = [Ca^{2+}][F^-]^2$$ $$\displaystyle IP= { 10 }^{ -2 } \times ({ 10 }^{ -3 })^2$$ $$\displaystyle IP={ 10 }^{ -8 }$$  The ionic product exceeds solubility product. $$\displaystyle { K }_{ sp }=\left( 1.7\times { 10 }^{ -10 } \right)$$A precipitate will be formed when $$\displaystyle IP > SP$$Chemistry

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