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Question

The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of his son . Find the present age of the father.


A
33
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B
48
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C
29
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D
38
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Solution

The correct option is A $$33$$
Let the present age of father is x years and son is y years
Then according to the question
$$x-3y=3$$.............(i)
After 3 years
$$(x+3)-2(y+3)=10$$
$$x+3-2y-6=10$$
$$x-2y=13$$...........(ii)
Subtracting eq(i)and eq(ii)
$$y=10$$
Putting y=10 in eq(i)
$$x-3\times 10=3$$
$$x=33 $$
Hence Father present age is 33 years.

Maths

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