The pressure of a medium is changed from 1-01 - 105 Pa to 1-165 - 105 Pa and change in volume is 10 - keeping temperature constant- The bulk modulus of the medium is

The correct option is D 1.55 X 105PaHere P=(1.165×10^5 1.01×10^5) =0.155× 10^5 Pa × V/V=10/100=1/10 Bulk modulus k= p/ v/v =0.155×10^5/1/10 =1.55×10^5Pa ...

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Standard VII

Physics

Bulk Modulus

The pressure ...

Question

The pressure of a medium is changed from $1.01 \times 10^{5}$ Pa to $1.165 \times 10^{5}$ Pa and change in volume is 10% keeping temperature constant. The bulk modulus of the medium is

204.8 X 10⁵ Pa

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102.4 X 10⁵ Pa

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51.2 X 10⁵ Pa

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1.55 X 10⁵Pa

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Solution

The correct option is D. $1.55 \times 10^{5}$ Pa
Here
$△ P = (1.165 \times 10^{5} - 1.01 \times 10^{5})$
$= 0.155 \times 10^{5}$ Pa
$△ V / V = 10 / 100 = 1 / 10$
We know,
Bulk modulus $B = \frac{△ P}{△ V / V}$
$B = \frac{0.155 \times 10^{5}}{\frac{1}{10}}$
$B = 1.55 \times 10^{5} P a$ .

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The pressure of a medium is changed from 1.01× 105 Pa to 1.165× 105 Pa and change in volume is 10% keeping temperature constant. The bulk modulus of the medium is

The correct option is D. 1.55×105 PaHere △ P=(1.165×105−1.01×105) =0.155× 105 Pa △V/V=10/100=1/10We know,Bulk modulus B=△ P△ V/V B=0.155×105110 B=1.55×105Pa.

The pressure of a medium is changed from $1.01 \times 10^{5}$ Pa to $1.165 \times 10^{5}$ Pa and change in volume is 10% keeping temperature constant. The bulk modulus of the medium is

The correct option is D. $1.55 \times 10^{5}$ Pa
Here
$△ P = (1.165 \times 10^{5} - 1.01 \times 10^{5})$
$= 0.155 \times 10^{5}$ Pa
$△ V / V = 10 / 100 = 1 / 10$
We know,
Bulk modulus $B = \frac{△ P}{△ V / V}$
$B = \frac{0.155 \times 10^{5}}{\frac{1}{10}}$
$B = 1.55 \times 10^{5} P a$ .