Question

The pressure of an ideal gas is written as $P=\frac{2E}{3V}$. Here $E$ stands for

• A. total translational kinetic energy
• B. rotational kinetic energy
• C. average translation kinetic energy
• D. total kinetic energy

Answer 1

The correct option is A total translational kinetic energy

Given $P=\frac{2E}{3V}$

$\Rightarrow PV=\frac{2}{3}E$

$\Rightarrow nRT=\frac{2}{3}E$ $\{asPV=nRTidealgasequation\}$

$\Rightarrow \frac{3}{2}nRT=E$

$\Rightarrow \frac{3}{2}KT=E$ $\{K=nR\}$

According to law of equipartition of energy it has $3$ degree of freedon thus it is translation kinetic energy.

Hence, the answer is total translational kinetic energy.