Question

# The pressure of an ideal gas is written as $$P=\dfrac {2E}{3V}$$. Here $$E$$ stands for

A
total translational kinetic energy
B
rotational kinetic energy
C
average translation kinetic energy
D
total kinetic energy

Solution

## The correct option is A total translational kinetic energyGiven $$P=\dfrac{2E}{3V}$$$$\Rightarrow PV=\dfrac{2}{3}E$$$$\Rightarrow nRT=\dfrac{2}{3}E$$        $$\left\{ as\;PV=nRT\;ideal\;gas\;equation \right\}$$$$\Rightarrow\dfrac{3}{2}nRT=E$$$$\Rightarrow \dfrac{3}{2}KT=E$$           $$\left\{K=nR\right\}$$According to law of equipartition of energy it has $$3$$ degree of freedon thus it is translation kinetic energy. Hence, the answer is total translational kinetic energy.Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More