The pressure P1 at the top a dam and P2 at a depth h from the top inside water are related as:

P1 > P2

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P1 = P2

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P1 - P2 = $h ρ g$

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P2 - P1 = $h ρ g$

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Solution

The correct option is D
P2 - P1 = $h ρ g$

Pressure at a point in a liquid is due to the weight of the liquid acting on the surface of any objects in the liquid.

P = $ρ g h$

Therefore pressure acting at a distance h = pressure exerted by the water column above the point = P2 - P1 = $h ρ g$

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