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Question

The primary and secondary coil of a transformer have 50 and 1500 turns respectively. If the magnetic flux ϕ linked with primary coil is given by ϕ=ϕ0+4t, where is in webers, t is time in seconds and ϕ is a constant, the output voltage across the secondary coil is:

A
150 V
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B
90 V
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C
120 V
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D
180 V
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Solution

The correct option is C 120 V
Magnetic flux linked with the primary coil ϕ=ϕo+4t
So, induced emf in the primary coil |Vp|=dϕdt=ddt(ϕo+4t)=4 V
Number of turns in primary coil Np=50
Number of turns in secondary coil Ns=1500
So, output voltage in secondary coil Vs=NsNpVp
Vs=150050×4=120 V

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